b^4+2b^2+15=0

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Solution for b^4+2b^2+15=0 equation:


Simplifying
b4 + 2b2 + 15 = 0

Reorder the terms:
15 + 2b2 + b4 = 0

Solving
15 + 2b2 + b4 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-15' to each side of the equation.
15 + 2b2 + -15 + b4 = 0 + -15

Reorder the terms:
15 + -15 + 2b2 + b4 = 0 + -15

Combine like terms: 15 + -15 = 0
0 + 2b2 + b4 = 0 + -15
2b2 + b4 = 0 + -15

Combine like terms: 0 + -15 = -15
2b2 + b4 = -15

The b term is 2b2.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2b2 + 1 + b4 = -15 + 1

Reorder the terms:
1 + 2b2 + b4 = -15 + 1

Combine like terms: -15 + 1 = -14
1 + 2b2 + b4 = -14

Factor a perfect square on the left side:
(b2 + 1)(b2 + 1) = -14

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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